Sunday, September 12, 2010

Car Crash Analysis

This graph shows the velocity of the passenger before the car crash. In the shaded portion of both graphs, the slope of the line is fairly constant, it it when the slope begins to change that the crash actually begins. The top graph is the position, so since the derivative of the position is equal to the velocity, x'(t) = v(t) = -1.068 m/s. This can be checked for exactitude alongside the mean and median of the lower graph, the velocity graph.

This graph shows the acceleration of the passenger during the car crash. The lower graph is the velocity, so since the derivative of the velocity is equal to the acceleration, v'(t) = a(t) = .8787 m/s/s

This graph also shows the position of the passenger during the car crash. By using a quadratic function that the top graph computes, one can find the position: x = at^2+bt+c. In this case: position = .04309t^2 - 5.149t + 17.25


I would not own a Mini Cooper simply because I don't think anyone other than myself in my family could fit into it! Physics-wise, I feel like since the front of the car crumpled, as it should, I would buy a Mini.